NYT Pips Today: Hints, Answers And Walkthrough For Sunday, April 26

InnovationGamingNYT Pips Today: Hints, Answers And Walkthrough For Sunday, April 26ByErik Kain,Senior Contributor.Forbes contributors publish independent expert analyses and insights. I write about TV shows, movies, video games, entertainment & culture.Follow AuthorApr 26, 2026, 04:30pm EDT--:-- / --:--This voice experience is generated by AI. Learn more.This voice experience is generated by AI. Learn more. Today's PipsCredit: NYTThe dog days of April are upon us, and by the end of this week we’ll be in May. School is wrapping up for students around the country. If you’re about to head into finals week, may the study gods be with you. If you’re about to be on summer break, hang in there. For now, grab your dominos and let’s solve today’s Pips!Looking for Sunday’s Pips? Read our guide right here.How To Play PipsIn Pips, you have a grid of multicolored boxes. Each colored area represents a different “condition” that you have to achieve. You have a select number of dominoes that you have to spend filling in the grid. You must use every domino and achieve every condition properly to win. There are Easy, Medium and Difficult tiers.Here’s an example of a difficult tier Pips:Pips exampleScreenshot: Erik KainMORE FOR YOUAs you can see, the grid has a bunch of symbols and numbers with each color. On the far left, the three purple squares must not equal one another (hence the equal sign crossed out). The two pink squares next to that must equal a total of 0. The zig-zagging blue squares all must equal one another. You click on dominoes to rotate them, and will need to since they have to be rotated to fit where they belong. Not shown on this grid are other conditions, such as “less than” or “greater than.” If there are multiple tiles with > or < signs, the total of those tiles must be greater or less than the listed number. It varies by grid. Blank spaces can have anything. The various possible conditions are:= All pips must equal one another in this group.≠ All...