Northern Lights Forecast: Aurora Could Be Visible In These 9 States Sunday

BreakingBusinessBreaking NewsNorthern Lights Forecast: Aurora Could Be Visible In These 9 States SundayByZachary Folk,Forbes Staff. I cover breaking news.Follow AuthorJun 07, 2026, 10:14am EDTToplineThe northern lights could be visible from several states along the U.S.-Canadian border on Sunday, according to a forecast from the National Oceanic and Atmospheric Administration, as an incoming coronal mass ejection from the sun is expected to cause stronger geomagnetic storms later this week.NOAA is predicting geomagnetic storms could make the northern lights visible farther south later this week.Anadolu via Getty ImagesKey FactsNOAA is predicting a Kp index of five out of nine for Sunday night, meaning the northern lights could appear brighter, visible farther from the north pole and appear with more “motion and formations.”Forecasters expect a coronal mass ejection that escaped from the sun on Saturday will arrive by Monday, causing minor, moderate or even strong geomagnetic storms in the next few days—which could make the aurora more visible than usual. if (!window.cnxel) { window.cnxel = {}; window.cnxel.cmd = []; var iframe = document.createElement('iframe'); iframe.style.display = 'none'; iframe.onload = function() { var iframeDoc = iframe.contentWindow.document; var script = iframeDoc.createElement('script'); script.src = '//cd.elements.video/player.js?cid=62cec241-7d09-4462-afc2-f72f8d8ef40a'; script.setAttribute('defer', '1'); script.setAttribute('type', 'text/javascript'); iframeDoc.body.appendChild(script); }; document.head.appendChild(iframe); const preloadResourcesEndpoint = 'https://cds.elements.video/a/preload-resources-ovp.json'; fetch(preloadResourcesEndpoint, { priority: 'low' }) .then(response => { if (!response.ok) { throw new Error('Network response was not ok', preloadResourcesEndpoint); } return response.json(); }) .then(data => { const cssUrl = data.css; const cssUrlLink = document.createElement('link'); cssUrlLink.rel = 'stylesheet'; cssUrlLin...