Northern Lights Forecast: 8 States Have Another Chance To See The Aurora Friday

BreakingBusinessNorthern Lights Forecast: 8 States Have Another Chance To See The Aurora FridayByAntonio Pequeño IV,Forbes Staff. Pequeño is a breaking news reporter who covers tech and more.Follow AuthorMay 15, 2026, 12:48pm EDT--:-- / --:--This voice experience is generated by AI. Learn more.This voice experience is generated by AI. Learn more.ToplineThe northern lights may make another appearance in eight states Friday night, according to the National Oceanic and Atmospheric Administration, which issued a forecast giving a few areas along the northern U.S. border a chance at seeing the aurora borealis.The northern lights have a low chance of being seen along the northern U.S. border.Photo by SAUL LOEB/AFP via Getty ImagesKey FactsNOAA issued a Kp index of four, meaning the aurora will become brighter and be “quite pleasing to look at” for observers in the right places.Observers hoping to get a look at the northern lights may have a similar shot at seeing the aurora on Saturday, which has an identical forecast to Friday’s.No geomagnetic storm impacts, which can enhance northern lights showings, are forecast by NOAA for Friday. if (!window.cnxel) { window.cnxel = {}; window.cnxel.cmd = []; var iframe = document.createElement('iframe'); iframe.style.display = 'none'; iframe.onload = function() { var iframeDoc = iframe.contentWindow.document; var script = iframeDoc.createElement('script'); script.src = '//cd.elements.video/player.js?cid=62cec241-7d09-4462-afc2-f72f8d8ef40a'; script.setAttribute('defer', '1'); script.setAttribute('type', 'text/javascript'); iframeDoc.body.appendChild(script); }; document.head.appendChild(iframe); const preloadResourcesEndpoint = 'https://cds.elements.video/a/preload-resources-ovp.json'; fetch(preloadResourcesEndpoint, { priority: 'low' }) .then(response => { if (!response.ok) { throw new Error('Network response was not ok', preloadResourcesEndpoint); } return response.json(); }) .then(data => { const cssUrl = data.css; const cssUrlLin...